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Use the definition of a Taylor series to find the first four nonzero terms of the series for $ f(x) $ centered at the given value of $ a. $

$$ f(x) = \sqrt [3]{x}, \quad a = 8 $$

$$2+\frac{1}{12}(x-8)-\frac{1}{3^{2} \cdot 2^{5}}\left(x{-8}\right)^{2}+\frac{10}{3^{3}} \cdot \frac{1}{2^{5} \cdot 3 !}(x-8)^{3}$$

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Missouri State University

Baylor University

University of Nottingham

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